## 690. Employee Importance

You are given a data structure of employee information, which includes the employee's unique id, his importance value and his direct subordinates' id.

For example, employee 1 is the leader of employee 2, and employee 2 is the leader of employee 3. They have importance value 15, 10 and 5, respectively. Then employee 1 has a data structure like [1, 15, [2]], and employee 2 has [2, 10, [3]], and employee 3 has [3, 5, []]. Note that although employee 3 is also a subordinate of employee 1, the relationship is not direct.

Now given the employee information of a company, and an employee id, you need to return the total importance value of this employee and all his subordinates.

Example 1:

```Input: [[1, 5, [2, 3]], [2, 3, []], [3, 3, []]], 1
Output: 11
Explanation:
Employee 1 has importance value 5, and he has two direct subordinates: employee 2 and employee 3. They both have importance value 3. So the total importance value of employee 1 is 5 + 3 + 3 = 11.
```

Note:

1. One employee has at most one direct leader and may have several subordinates.
2. The maximum number of employees won't exceed 2000.

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#### Approach #1: Depth-First Search [Accepted]

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Intuition and Algorithm

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Let\'s use a hashmap `emap = {employee.id -> employee}` to query employees quickly.

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Now to find the total importance of an employee, it will be the importance of that employee, plus the total importance of each of that employee\'s subordinates. This is a straightforward depth-first search.

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Complexity Analysis

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Time Complexity: , where is the number of employees. We might query each employee in `dfs`.

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Space Complexity: , the size of the implicit call stack when evaluating `dfs`.

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Analysis written by: @awice.

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